60-(5/3b)=25

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Solution for 60-(5/3b)=25 equation: 



60-(5/3b)=25

We move all terms to the left:

60-(5/3b)-(25)=0



Domain of the equation: 3b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

-(+5/3b)+60-25=0

We add all the numbers together, and all the variables

-(+5/3b)+35=0

We get rid of parentheses

-5/3b+35=0

We multiply all the terms by the denominator


35*3b-5=0

Wy multiply elements

105b-5=0

We move all terms containing b to the left, all other terms to the right

105b=5

b=5/105

b=1/21

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