10=(2/5x+3)=4x+30

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Solution for 10=(2/5x+3)=4x+30 equation: 



10=(2/5x+3)=4x+30

We move all terms to the left:

10-((2/5x+3))=0



Domain of the equation: 5x+3))!=0

x∈R



We multiply all the terms by the denominator


-((2+10*5x+3))=0



We calculate terms in parentheses: -((2+10*5x+3)), so:

(2+10*5x+3)

We add all the numbers together, and all the variables

(10*5x+5)

We get rid of parentheses

10*5x+5

Wy multiply elements

50x+5

Back to the equation:

-(50x+5)



We get rid of parentheses

-50x-5=0

We move all terms containing x to the left, all other terms to the right

-50x=5

x=5/-50

x=-1/10

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