10=(1/9-1-3x)

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Solution for 10=(1/9-1-3x) equation: 



10=(1/9-1-3x)

We move all terms to the left:

10-((1/9-1-3x))=0



Domain of the equation: 9-1-3x))!=0

We move all terms containing x to the left, all other terms to the right

-3x))!=-8

x!=-8/1

x!=-8

x∈R



We add all the numbers together, and all the variables

-((-3x+1/9-1))+10=0

We multiply all the terms by the denominator


-((-3x+1+10*9-1))=0



We calculate terms in parentheses: -((-3x+1+10*9-1)), so:

(-3x+1+10*9-1)

We add all the numbers together, and all the variables

(-3x+90)

We get rid of parentheses

-3x+90

Back to the equation:

-(-3x+90)



We get rid of parentheses

3x-90=0

We move all terms containing x to the left, all other terms to the right

3x=90

x=90/3

x=30

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