x(2x-3)=2x(x-5)+15

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Solution for x(2x-3)=2x(x-5)+15 equation: 



x(2x-3)=2x(x-5)+15

We move all terms to the left:

x(2x-3)-(2x(x-5)+15)=0

We multiply parentheses

2x^2-3x-(2x(x-5)+15)=0



We calculate terms in parentheses: -(2x(x-5)+15), so:

2x(x-5)+15

We multiply parentheses

2x^2-10x+15

Back to the equation:

-(2x^2-10x+15)



We get rid of parentheses

2x^2-2x^2-3x+10x-15=0

We add all the numbers together, and all the variables

7x-15=0

We move all terms containing x to the left, all other terms to the right

7x=15

x=15/7

x=2+1/7

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