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1080=1000r^2
We move all terms to the left:
1080-(1000r^2)=0
a = -1000; b = 0; c = +1080;
Δ = b2-4ac
Δ = 02-4·(-1000)·1080
Δ = 4320000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4320000}=\sqrt{1440000*3}=\sqrt{1440000}*\sqrt{3}=1200\sqrt{3}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1200\sqrt{3}}{2*-1000}=\frac{0-1200\sqrt{3}}{-2000} =-\frac{1200\sqrt{3}}{-2000} =-\frac{3\sqrt{3}}{-5} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1200\sqrt{3}}{2*-1000}=\frac{0+1200\sqrt{3}}{-2000} =\frac{1200\sqrt{3}}{-2000} =\frac{3\sqrt{3}}{-5} $
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