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14-3(x+10)=7(2x+4)+x
We move all terms to the left:
14-3(x+10)-(7(2x+4)+x)=0
We multiply parentheses
-3x-(7(2x+4)+x)-30+14=0
We calculate terms in parentheses: -(7(2x+4)+x), so:We add all the numbers together, and all the variables
7(2x+4)+x
We add all the numbers together, and all the variables
x+7(2x+4)
We multiply parentheses
x+14x+28
We add all the numbers together, and all the variables
15x+28
Back to the equation:
-(15x+28)
-3x-(15x+28)-16=0
We get rid of parentheses
-3x-15x-28-16=0
We add all the numbers together, and all the variables
-18x-44=0
We move all terms containing x to the left, all other terms to the right
-18x=44
x=44/-18
x=-2+4/9
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