100x+400=40(2x-8)+200

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Solution for 100x+400=40(2x-8)+200 equation: 



100x+400=40(2x-8)+200

We move all terms to the left:

100x+400-(40(2x-8)+200)=0



We calculate terms in parentheses: -(40(2x-8)+200), so:

40(2x-8)+200

We multiply parentheses

80x-320+200

We add all the numbers together, and all the variables

80x-120

Back to the equation:

-(80x-120)



We get rid of parentheses

100x-80x+120+400=0

We add all the numbers together, and all the variables

20x+520=0

We move all terms containing x to the left, all other terms to the right

20x=-520

x=-520/20

x=-26

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