100=100+(100)(r)(2)

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Solution for 100=100+(100)(r)(2) equation: 



100=100+(100)(r)(2)

We move all terms to the left:

100-(100+(100)(r)(2))=0

We add all the numbers together, and all the variables

-(+100r^2+100)+100=0

We get rid of parentheses

-100r^2-100+100=0

We add all the numbers together, and all the variables

-100r^2=0

a = -100; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-100)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{0}{-200}=0$

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