X2-13x+5=0

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Solution for X2-13x+5=0 equation:



X2-13X+5=0
We add all the numbers together, and all the variables
X^2-13X+5=0
a = 1; b = -13; c = +5;
Δ = b2-4ac
Δ = -132-4·1·5
Δ = 149
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{149}}{2*1}=\frac{13-\sqrt{149}}{2} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{149}}{2*1}=\frac{13+\sqrt{149}}{2} $

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