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1008=(2x-8)(x+6)
We move all terms to the left:
1008-((2x-8)(x+6))=0
We multiply parentheses ..
-((+2x^2+12x-8x-48))+1008=0
We calculate terms in parentheses: -((+2x^2+12x-8x-48)), so:We get rid of parentheses
(+2x^2+12x-8x-48)
We get rid of parentheses
2x^2+12x-8x-48
We add all the numbers together, and all the variables
2x^2+4x-48
Back to the equation:
-(2x^2+4x-48)
-2x^2-4x+48+1008=0
We add all the numbers together, and all the variables
-2x^2-4x+1056=0
a = -2; b = -4; c = +1056;
Δ = b2-4ac
Δ = -42-4·(-2)·1056
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8464}=92$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-92}{2*-2}=\frac{-88}{-4} =+22 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+92}{2*-2}=\frac{96}{-4} =-24 $
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