48=(3c+4)=4(c+5)+c

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Solution for 48=(3c+4)=4(c+5)+c equation: 



48=(3c+4)=4(c+5)+c

We move all terms to the left:

48-((3c+4))=0



We calculate terms in parentheses: -((3c+4)), so:

(3c+4)

We get rid of parentheses

3c+4

Back to the equation:

-(3c+4)



We get rid of parentheses

-3c-4+48=0

We add all the numbers together, and all the variables

-3c+44=0

We move all terms containing c to the left, all other terms to the right

-3c=-44

c=-44/-3

c=14+2/3

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