1000(8x-10)=60(230+100x)

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Solution for 1000(8x-10)=60(230+100x) equation: 



1000(8x-10)=60(230+100x)

We move all terms to the left:

1000(8x-10)-(60(230+100x))=0

We add all the numbers together, and all the variables

1000(8x-10)-(60(100x+230))=0

We multiply parentheses

8000x-(60(100x+230))-10000=0



We calculate terms in parentheses: -(60(100x+230)), so:

60(100x+230)

We multiply parentheses

6000x+13800

Back to the equation:

-(6000x+13800)



We get rid of parentheses

8000x-6000x-13800-10000=0

We add all the numbers together, and all the variables

2000x-23800=0

We move all terms containing x to the left, all other terms to the right

2000x=23800

x=23800/2000

x=11+9/10

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