3(x2+2)=6-x2

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Solution for 3(x2+2)=6-x2 equation: 



3(x2+2)=6-x2

We move all terms to the left:

3(x2+2)-(6-x2)=0

We add all the numbers together, and all the variables

3(+x^2+2)-(-1x^2+6)=0

We multiply parentheses

3x^2-(-1x^2+6)+6=0

We get rid of parentheses

3x^2+1x^2-6+6=0

We add all the numbers together, and all the variables

4x^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$

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