1000(7x-10)=309(1440+100x)

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Solution for 1000(7x-10)=309(1440+100x) equation: 



1000(7x-10)=309(1440+100x)

We move all terms to the left:

1000(7x-10)-(309(1440+100x))=0

We add all the numbers together, and all the variables

1000(7x-10)-(309(100x+1440))=0

We multiply parentheses

7000x-(309(100x+1440))-10000=0



We calculate terms in parentheses: -(309(100x+1440)), so:

309(100x+1440)

We multiply parentheses

30900x+444960

Back to the equation:

-(30900x+444960)



We get rid of parentheses

7000x-30900x-444960-10000=0

We add all the numbers together, and all the variables

-23900x-454960=0

We move all terms containing x to the left, all other terms to the right

-23900x=454960

x=454960/-23900

x=-19+43/1195

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