1/4(8x-4)=3/2(2x+10)

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Solution for 1/4(8x-4)=3/2(2x+10) equation: 



1/4(8x-4)=3/2(2x+10)

We move all terms to the left:

1/4(8x-4)-(3/2(2x+10))=0



Domain of the equation: 4(8x-4)!=0

x∈R





Domain of the equation: 2(2x+10))!=0

x∈R



We calculate fractions


(2x2/(4(8x-4)*2(2x+10)))+(-12x8/(4(8x-4)*2(2x+10)))=0



We calculate terms in parentheses: +(2x2/(4(8x-4)*2(2x+10))), so:

2x2/(4(8x-4)*2(2x+10))

We multiply all the terms by the denominator


2x2

We add all the numbers together, and all the variables

2x^2

Back to the equation:

+(2x^2)





We calculate terms in parentheses: +(-12x8/(4(8x-4)*2(2x+10))), so:

-12x8/(4(8x-4)*2(2x+10))

We multiply all the terms by the denominator


-12x8

We add all the numbers together, and all the variables

-12x^8

We do not support expression: x^8

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