100-4x2/5-x

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Solution for 100-4x2/5-x equation: 


x in (-oo:+oo)

100-((4*x^2)/5)-x = 0

(-4/5)*x^2-x+100 = 0

100-4/5*x^2-x = 0

DELTA = (-1)^2-(-4/5*4*100)

DELTA = 321

DELTA > 0

x = (321^(1/2)+1)/(-4/5*2) or x = (1-321^(1/2))/(-4/5*2)

x = -5/8*(321^(1/2)+1) or x = -5/8*(1-321^(1/2))

x in { -5/8*(321^(1/2)+1), -5/8*(1-321^(1/2)) }

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