7/12(1x-3)=1/3x+4/1

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Solution for 7/12(1x-3)=1/3x+4/1 equation: 


x in (-oo:+oo)

(7/12)*(1*x-3) = (1/3)*x+4/1 // - (1/3)*x+4/1

(7/12)*(1*x-3)-((1/3)*x)-(4/1) = 0

(7/12)*(x-3)+(-1/3)*x-4 = 0

7/12*(x-3)-x/3-4 = 0

(7/12*3*(x-3))/3-x/3+(-4*3)/3 = 0

7/12*3*(x-3)-x-4*3 = 0

3/4*x-12-21/4 = 0

3/4*x-69/4 = 0

(3/4*x-69/4)/3 = 0

(3/4*x-69/4)/3 = 0 // * 3

3/4*x-69/4 = 0

3/4*x-69/4 = 0 // + 69/4

3/4*x = 69/4 // : 3/4

x = 69/4/3/4

x = 23

x = 23

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