100(6x-10)=40(255+100x)

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Solution for 100(6x-10)=40(255+100x) equation: 



100(6x-10)=40(255+100x)

We move all terms to the left:

100(6x-10)-(40(255+100x))=0

We add all the numbers together, and all the variables

100(6x-10)-(40(100x+255))=0

We multiply parentheses

600x-(40(100x+255))-1000=0



We calculate terms in parentheses: -(40(100x+255)), so:

40(100x+255)

We multiply parentheses

4000x+10200

Back to the equation:

-(4000x+10200)



We get rid of parentheses

600x-4000x-10200-1000=0

We add all the numbers together, and all the variables

-3400x-11200=0

We move all terms containing x to the left, all other terms to the right

-3400x=11200

x=11200/-3400

x=-3+5/17

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