3(z+2)=7z+4

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Solution for 3(z+2)=7z+4 equation: 



3(z+2)=7z+4

We move all terms to the left:

3(z+2)-(7z+4)=0

We multiply parentheses

3z-(7z+4)+6=0

We get rid of parentheses

3z-7z-4+6=0

We add all the numbers together, and all the variables

-4z+2=0

We move all terms containing z to the left, all other terms to the right

-4z=-2

z=-2/-4

z=1/2

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