10/x-3+1=x/2

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Solution for 10/x-3+1=x/2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

10/x-3+1 = x/2 // - x/2

10/x-(x/2)-3+1 = 0

10*x^-1-1/2*x^1-2*x^0 = 0

(10*x^0-1/2*x^2-2*x^1)/(x^1) = 0 // * x^2

x^1*(10*x^0-1/2*x^2-2*x^1) = 0

x^1

(-1/2)*x^2-2*x+10 = 0

(-1/2)*x^2-2*x+10 = 0

DELTA = (-2)^2-(4*10*(-1/2))

DELTA = 24

DELTA > 0

x = (24^(1/2)+2)/(2*(-1/2)) or x = (2-24^(1/2))/(2*(-1/2))

x = -(2*6^(1/2)+2) or x = -(2-2*6^(1/2))

x in { -(2*6^(1/2)+2), -(2-2*6^(1/2))} 

x in { -(2*6^(1/2)+2), -(2-2*6^(1/2)) }

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