6(x-4)+2x=8(x+2)-40

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Solution for 6(x-4)+2x=8(x+2)-40 equation:


Simplifying
6(x + -4) + 2x = 8(x + 2) + -40

Reorder the terms:
6(-4 + x) + 2x = 8(x + 2) + -40
(-4 * 6 + x * 6) + 2x = 8(x + 2) + -40
(-24 + 6x) + 2x = 8(x + 2) + -40

Combine like terms: 6x + 2x = 8x
-24 + 8x = 8(x + 2) + -40

Reorder the terms:
-24 + 8x = 8(2 + x) + -40
-24 + 8x = (2 * 8 + x * 8) + -40
-24 + 8x = (16 + 8x) + -40

Reorder the terms:
-24 + 8x = 16 + -40 + 8x

Combine like terms: 16 + -40 = -24
-24 + 8x = -24 + 8x

Add '24' to each side of the equation.
-24 + 24 + 8x = -24 + 24 + 8x

Combine like terms: -24 + 24 = 0
0 + 8x = -24 + 24 + 8x
8x = -24 + 24 + 8x

Combine like terms: -24 + 24 = 0
8x = 0 + 8x
8x = 8x

Add '-8x' to each side of the equation.
8x + -8x = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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