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10/x+3=20-3x
We move all terms to the left:
10/x+3-(20-3x)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
10/x-(-3x+20)+3=0
We get rid of parentheses
10/x+3x-20+3=0
We multiply all the terms by the denominator
3x*x-20*x+3*x+10=0
We add all the numbers together, and all the variables
-17x+3x*x+10=0
Wy multiply elements
3x^2-17x+10=0
a = 3; b = -17; c = +10;
Δ = b2-4ac
Δ = -172-4·3·10
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-13}{2*3}=\frac{4}{6} =2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+13}{2*3}=\frac{30}{6} =5 $
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