(2X-4)(x)=160

Solution for (2X-4)(x)=160 equation:

(2X-4)(X)=160

We move all terms to the left:

(2X-4)(X)-(160)=0

We multiply parentheses

2X^2-4X-160=0

a = 2; b = -4; c = -160;
Δ = b2-4ac
Δ = -42-4·2·(-160)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-36}{2*2}=\frac{-32}{4}
=-8
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+36}{2*2}=\frac{40}{4}
=10
$