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10/x+1=3x
We move all terms to the left:
10/x+1-(3x)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
-3x+10/x+1=0
We multiply all the terms by the denominator
-3x*x+1*x+10=0
We add all the numbers together, and all the variables
x-3x*x+10=0
Wy multiply elements
-3x^2+x+10=0
a = -3; b = 1; c = +10;
Δ = b2-4ac
Δ = 12-4·(-3)·10
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-11}{2*-3}=\frac{-12}{-6} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+11}{2*-3}=\frac{10}{-6} =-1+2/3 $
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