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10/m-3=6/8m
We move all terms to the left:
10/m-3-(6/8m)=0
Domain of the equation: m!=0
m∈R
Domain of the equation: 8m)!=0We add all the numbers together, and all the variables
m!=0/1
m!=0
m∈R
10/m-(+6/8m)-3=0
We get rid of parentheses
10/m-6/8m-3=0
We calculate fractions
80m/8m^2+(-6m)/8m^2-3=0
We multiply all the terms by the denominator
80m+(-6m)-3*8m^2=0
Wy multiply elements
-24m^2+80m+(-6m)=0
We get rid of parentheses
-24m^2+80m-6m=0
We add all the numbers together, and all the variables
-24m^2+74m=0
a = -24; b = 74; c = 0;
Δ = b2-4ac
Δ = 742-4·(-24)·0
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5476}=74$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(74)-74}{2*-24}=\frac{-148}{-48} =3+1/12 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(74)+74}{2*-24}=\frac{0}{-48} =0 $
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