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(2x+1)(x+2)=-3
We move all terms to the left:
(2x+1)(x+2)-(-3)=0
We add all the numbers together, and all the variables
(2x+1)(x+2)+3=0
We multiply parentheses ..
(+2x^2+4x+x+2)+3=0
We get rid of parentheses
2x^2+4x+x+2+3=0
We add all the numbers together, and all the variables
2x^2+5x+5=0
a = 2; b = 5; c = +5;
Δ = b2-4ac
Δ = 52-4·2·5
Δ = -15
Delta is less than zero, so there is no solution for the equation
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