10/3x=x+1

Solution for 10/3x=x+1 equation:

10/3x=x+1

We move all terms to the left:

10/3x-(x+1)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We get rid of parentheses

10/3x-x-1=0

We multiply all the terms by the denominator


-x*3x-1*3x+10=0

Wy multiply elements

-3x^2-3x+10=0

a = -3; b = -3; c = +10;
Δ = b2-4ac
Δ = -32-4·(-3)·10
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{129}}{2*-3}=\frac{3-\sqrt{129}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{129}}{2*-3}=\frac{3+\sqrt{129}}{-6}
$