(x+40)+(4x-5)=(6x+20)

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Solution for (x+40)+(4x-5)=(6x+20) equation: 



(x+40)+(4x-5)=(6x+20)

We move all terms to the left:

(x+40)+(4x-5)-((6x+20))=0

We get rid of parentheses

x+4x-((6x+20))+40-5=0



We calculate terms in parentheses: -((6x+20)), so:

(6x+20)

We get rid of parentheses

6x+20

Back to the equation:

-(6x+20)



We add all the numbers together, and all the variables

5x-(6x+20)+35=0

We get rid of parentheses

5x-6x-20+35=0

We add all the numbers together, and all the variables

-1x+15=0

We move all terms containing x to the left, all other terms to the right

-x=-15

x=-15/-1

x=+15

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