10-5(h+3)+50=3(h+4)-2

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Solution for 10-5(h+3)+50=3(h+4)-2 equation: 



10-5(h+3)+50=3(h+4)-2

We move all terms to the left:

10-5(h+3)+50-(3(h+4)-2)=0

We add all the numbers together, and all the variables

-5(h+3)-(3(h+4)-2)+60=0

We multiply parentheses

-5h-(3(h+4)-2)-15+60=0



We calculate terms in parentheses: -(3(h+4)-2), so:

3(h+4)-2

We multiply parentheses

3h+12-2

We add all the numbers together, and all the variables

3h+10

Back to the equation:

-(3h+10)



We add all the numbers together, and all the variables

-5h-(3h+10)+45=0

We get rid of parentheses

-5h-3h-10+45=0

We add all the numbers together, and all the variables

-8h+35=0

We move all terms containing h to the left, all other terms to the right

-8h=-35

h=-35/-8

h=4+3/8

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