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4/5k-(k+1/5)=1/25(k+5)
We move all terms to the left:
4/5k-(k+1/5)-(1/25(k+5))=0
Domain of the equation: 5k!=0
k!=0/5
k!=0
k∈R
Domain of the equation: 25(k+5))!=0We add all the numbers together, and all the variables
k∈R
4/5k-(+k+1/5)-(1/25(k+5))=0
We get rid of parentheses
4/5k-k-(1/25(k+5))-1/5=0
We calculate fractions
-k+(100kk/(625k^2k+(-(1*5k*5)/(625k^2k+(-25kk/(625k^2k=0
We can not solve this equation
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