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10-3(x-1)=5x-(2x-1)
We move all terms to the left:
10-3(x-1)-(5x-(2x-1))=0
We multiply parentheses
-3x-(5x-(2x-1))+3+10=0
We calculate terms in parentheses: -(5x-(2x-1)), so:We add all the numbers together, and all the variables
5x-(2x-1)
We get rid of parentheses
5x-2x+1
We add all the numbers together, and all the variables
3x+1
Back to the equation:
-(3x+1)
-3x-(3x+1)+13=0
We get rid of parentheses
-3x-3x-1+13=0
We add all the numbers together, and all the variables
-6x+12=0
We move all terms containing x to the left, all other terms to the right
-6x=-12
x=-12/-6
x=+2
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