-10(7x-2)-10=1/2(10x+8)-8

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Solution for -10(7x-2)-10=1/2(10x+8)-8 equation: 



-10(7x-2)-10=1/2(10x+8)-8

We move all terms to the left:

-10(7x-2)-10-(1/2(10x+8)-8)=0



Domain of the equation: 2(10x+8)-8)!=0

x∈R



We multiply parentheses

-70x-(1/2(10x+8)-8)+20-10=0

We multiply all the terms by the denominator


-70x*2(10x+8)+20*2(10x+8)-8)-10*2(10x-8)-(1+8)-8)=0

We add all the numbers together, and all the variables

-70x*2(10x+8)+20*2(10x+8)-8)-10*2(10x-8)-9-8)=0

We add all the numbers together, and all the variables

-70x*2(10x+8)+20*2(10x+8)-8)-10*2(10x=0

Wy multiply elements

-140x^2(1+40x(1-8)-10*2(10x=0

We add all the numbers together, and all the variables

-140x^2(1+40x(-7)-10*2(10x=0

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