10-3(4a-3)=2(3a-4)-8

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Solution for 10-3(4a-3)=2(3a-4)-8 equation: 



10-3(4a-3)=2(3a-4)-8

We move all terms to the left:

10-3(4a-3)-(2(3a-4)-8)=0

We multiply parentheses

-12a-(2(3a-4)-8)+9+10=0



We calculate terms in parentheses: -(2(3a-4)-8), so:

2(3a-4)-8

We multiply parentheses

6a-8-8

We add all the numbers together, and all the variables

6a-16

Back to the equation:

-(6a-16)



We add all the numbers together, and all the variables

-12a-(6a-16)+19=0

We get rid of parentheses

-12a-6a+16+19=0

We add all the numbers together, and all the variables

-18a+35=0

We move all terms containing a to the left, all other terms to the right

-18a=-35

a=-35/-18

a=1+17/18

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