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5/9x+8=-x-6
We move all terms to the left:
5/9x+8-(-x-6)=0
Domain of the equation: 9x!=0We add all the numbers together, and all the variables
x!=0/9
x!=0
x∈R
5/9x-(-1x-6)+8=0
We get rid of parentheses
5/9x+1x+6+8=0
We multiply all the terms by the denominator
1x*9x+6*9x+8*9x+5=0
Wy multiply elements
9x^2+54x+72x+5=0
We add all the numbers together, and all the variables
9x^2+126x+5=0
a = 9; b = 126; c = +5;
Δ = b2-4ac
Δ = 1262-4·9·5
Δ = 15696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{15696}=\sqrt{144*109}=\sqrt{144}*\sqrt{109}=12\sqrt{109}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(126)-12\sqrt{109}}{2*9}=\frac{-126-12\sqrt{109}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(126)+12\sqrt{109}}{2*9}=\frac{-126+12\sqrt{109}}{18} $
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