10-2z+40=3(3z-9)

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Solution for 10-2z+40=3(3z-9) equation: 


Simplifying
10 + -2z + 40 = 3(3z + -9)

Reorder the terms:
10 + 40 + -2z = 3(3z + -9)

Combine like terms: 10 + 40 = 50
50 + -2z = 3(3z + -9)

Reorder the terms:
50 + -2z = 3(-9 + 3z)
50 + -2z = (-9 * 3 + 3z * 3)
50 + -2z = (-27 + 9z)

Solving
50 + -2z = -27 + 9z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-9z' to each side of the equation.
50 + -2z + -9z = -27 + 9z + -9z

Combine like terms: -2z + -9z = -11z
50 + -11z = -27 + 9z + -9z

Combine like terms: 9z + -9z = 0
50 + -11z = -27 + 0
50 + -11z = -27

Add '-50' to each side of the equation.
50 + -50 + -11z = -27 + -50

Combine like terms: 50 + -50 = 0
0 + -11z = -27 + -50
-11z = -27 + -50

Combine like terms: -27 + -50 = -77
-11z = -77

Divide each side by '-11'.
z = 7

Simplifying
z = 7

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