If it's not what You are looking for type in the equation solver your own equation and let us solve it.
k in (-oo:+oo)
140 = (k^20)/25 // - (k^20)/25
140-((k^20)/25) = 0
-1/25*k^20 = -140 // : -1/25
k^20 = 3500
k^20 = 3500 // ^ 1/20
abs(k) = 3500^(1/20)
k = 3500^(1/20) or k = -3500^(1/20)
k in { 3500^(1/20), -3500^(1/20) }
| 8u^4-24u^3/4u^2 | | 140=k(20)/25 | | lx+3l=4x+9 | | 1401=k(20)/25 | | -12(p-2)=6 | | 140=175(20)/c | | -7(4c+2)=5(2x+1) | | 0=5x+45 | | n/8=3/2 | | 4m^4n^3p^3/3m^2n^2p^4 | | X-36=-8x | | -7/x-2=10 | | -6x+-9y= | | 9x^2+56x+12=0 | | 98=8(1-2v)-2v | | q=175(28)/35 | | 9n^2-4n-16=0 | | q=(175)28/35 | | 11/20 | | (8+u)(2u-3)=0 | | 2x-3=-2x+17 | | h=-8t^2-4t+12 | | 140=k(28)/35 | | h=t^2-4t+12 | | -28+4k-14k=-2k-4 | | y=k28/35 | | 64/116 | | 3u^2+5=-16u | | 5x/2=18/2 | | 60-21u=-u | | 4y-8-2y+5=3(2y-6) | | 4x=10x+28 |