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10-2/3x=1/4x
We move all terms to the left:
10-2/3x-(1/4x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 4x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-2/3x-(+1/4x)+10=0
We get rid of parentheses
-2/3x-1/4x+10=0
We calculate fractions
(-8x)/12x^2+(-3x)/12x^2+10=0
We multiply all the terms by the denominator
(-8x)+(-3x)+10*12x^2=0
Wy multiply elements
120x^2+(-8x)+(-3x)=0
We get rid of parentheses
120x^2-8x-3x=0
We add all the numbers together, and all the variables
120x^2-11x=0
a = 120; b = -11; c = 0;
Δ = b2-4ac
Δ = -112-4·120·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-11}{2*120}=\frac{0}{240} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+11}{2*120}=\frac{22}{240} =11/120 $
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