1x-(2x+1)=8-(3x+3)

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Solution for 1x-(2x+1)=8-(3x+3) equation: 



1x-(2x+1)=8-(3x+3)

We move all terms to the left:

1x-(2x+1)-(8-(3x+3))=0

We add all the numbers together, and all the variables

x-(2x+1)-(8-(3x+3))=0

We get rid of parentheses

x-2x-(8-(3x+3))-1=0



We calculate terms in parentheses: -(8-(3x+3)), so:

8-(3x+3)

determiningTheFunctionDomain
-(3x+3)+8

We get rid of parentheses

-3x-3+8

We add all the numbers together, and all the variables

-3x+5

Back to the equation:

-(-3x+5)



We add all the numbers together, and all the variables

-1x-(-3x+5)-1=0

We get rid of parentheses

-1x+3x-5-1=0

We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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