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10-2/3b=52
We move all terms to the left:
10-2/3b-(52)=0
Domain of the equation: 3b!=0We add all the numbers together, and all the variables
b!=0/3
b!=0
b∈R
-2/3b-42=0
We multiply all the terms by the denominator
-42*3b-2=0
Wy multiply elements
-126b-2=0
We move all terms containing b to the left, all other terms to the right
-126b=2
b=2/-126
b=-1/63
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