-3(e-4)+2(5+2e)=29

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Solution for -3(e-4)+2(5+2e)=29 equation: 



-3(e-4)+2(5+2e)=29

We move all terms to the left:

-3(e-4)+2(5+2e)-(29)=0

We add all the numbers together, and all the variables

-3(e-4)+2(2e+5)-29=0

We multiply parentheses

-3e+4e+12+10-29=0

We add all the numbers together, and all the variables

e-7=0

We move all terms containing e to the left, all other terms to the right

e=7

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