10-2(3x+1)=13

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Solution for 10-2(3x+1)=13 equation: 



10-2(3x+1)=13

We move all terms to the left:

10-2(3x+1)-(13)=0

We add all the numbers together, and all the variables

-2(3x+1)-3=0

We multiply parentheses

-6x-2-3=0

We add all the numbers together, and all the variables

-6x-5=0

We move all terms containing x to the left, all other terms to the right

-6x=5

x=5/-6

x=-5/6

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