10-10(9-2b)=-7(b+9)+10b

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Solution for 10-10(9-2b)=-7(b+9)+10b equation: 



10-10(9-2b)=-7(b+9)+10b

We move all terms to the left:

10-10(9-2b)-(-7(b+9)+10b)=0

We add all the numbers together, and all the variables

-10(-2b+9)-(-7(b+9)+10b)+10=0

We multiply parentheses

20b-(-7(b+9)+10b)-90+10=0



We calculate terms in parentheses: -(-7(b+9)+10b), so:

-7(b+9)+10b

We add all the numbers together, and all the variables

10b-7(b+9)

We multiply parentheses

10b-7b-63

We add all the numbers together, and all the variables

3b-63

Back to the equation:

-(3b-63)



We add all the numbers together, and all the variables

20b-(3b-63)-80=0

We get rid of parentheses

20b-3b+63-80=0

We add all the numbers together, and all the variables

17b-17=0

We move all terms containing b to the left, all other terms to the right

17b=17

b=17/17

b=1

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