2(4f/3+12)=2(-16/3+12)

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Solution for 2(4f/3+12)=2(-16/3+12) equation: 



2(4f/3+12)=2(-16/3+12)

We move all terms to the left:

2(4f/3+12)-(2(-16/3+12))=0

We multiply parentheses

8f+24-(2(-16/3+12))=0

We multiply all the terms by the denominator


8f*3+12))+24*3+12))-(2(-16=0

We add all the numbers together, and all the variables

8f*3=0

Wy multiply elements

24f=0

f=0/24

f=0

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