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10-1/3x=3/x+5
We move all terms to the left:
10-1/3x-(3/x+5)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: x+5)!=0We get rid of parentheses
x∈R
-1/3x-3/x-5+10=0
We calculate fractions
(-x)/3x^2+(-9x)/3x^2-5+10=0
We add all the numbers together, and all the variables
(-1x)/3x^2+(-9x)/3x^2-5+10=0
We add all the numbers together, and all the variables
(-1x)/3x^2+(-9x)/3x^2+5=0
We multiply all the terms by the denominator
(-1x)+(-9x)+5*3x^2=0
Wy multiply elements
15x^2+(-1x)+(-9x)=0
We get rid of parentheses
15x^2-1x-9x=0
We add all the numbers together, and all the variables
15x^2-10x=0
a = 15; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·15·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*15}=\frac{0}{30} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*15}=\frac{20}{30} =2/3 $
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