9x+3(20-x)=32

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Solution for 9x+3(20-x)=32 equation: 



9x+3(20-x)=32

We move all terms to the left:

9x+3(20-x)-(32)=0

We add all the numbers together, and all the variables

9x+3(-1x+20)-32=0

We multiply parentheses

9x-3x+60-32=0

We add all the numbers together, and all the variables

6x+28=0

We move all terms containing x to the left, all other terms to the right

6x=-28

x=-28/6

x=-4+2/3

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