10-(w-4)=3w-(2-w)

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Solution for 10-(w-4)=3w-(2-w) equation: 



10-(w-4)=3w-(2-w)

We move all terms to the left:

10-(w-4)-(3w-(2-w))=0

We add all the numbers together, and all the variables

-(w-4)-(3w-(-1w+2))+10=0

We get rid of parentheses

-w-(3w-(-1w+2))+4+10=0



We calculate terms in parentheses: -(3w-(-1w+2)), so:

3w-(-1w+2)

We get rid of parentheses

3w+1w-2

We add all the numbers together, and all the variables

4w-2

Back to the equation:

-(4w-2)



We add all the numbers together, and all the variables

-1w-(4w-2)+14=0

We get rid of parentheses

-1w-4w+2+14=0

We add all the numbers together, and all the variables

-5w+16=0

We move all terms containing w to the left, all other terms to the right

-5w=-16

w=-16/-5

w=3+1/5

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