2(3y-1)=1+3(y+5)

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Solution for 2(3y-1)=1+3(y+5) equation: 



2(3y-1)=1+3(y+5)

We move all terms to the left:

2(3y-1)-(1+3(y+5))=0

We multiply parentheses

6y-(1+3(y+5))-2=0



We calculate terms in parentheses: -(1+3(y+5)), so:

1+3(y+5)

determiningTheFunctionDomain
3(y+5)+1

We multiply parentheses

3y+15+1

We add all the numbers together, and all the variables

3y+16

Back to the equation:

-(3y+16)



We get rid of parentheses

6y-3y-16-2=0

We add all the numbers together, and all the variables

3y-18=0

We move all terms containing y to the left, all other terms to the right

3y=18

y=18/3

y=6

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