10-(8-n)+14n=-4+12(n+1)

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Solution for 10-(8-n)+14n=-4+12(n+1) equation: 



10-(8-n)+14n=-4+12(n+1)

We move all terms to the left:

10-(8-n)+14n-(-4+12(n+1))=0

We add all the numbers together, and all the variables

-(-1n+8)+14n-(-4+12(n+1))+10=0

We add all the numbers together, and all the variables

14n-(-1n+8)-(-4+12(n+1))+10=0

We get rid of parentheses

14n+1n-(-4+12(n+1))-8+10=0



We calculate terms in parentheses: -(-4+12(n+1)), so:

-4+12(n+1)

determiningTheFunctionDomain
12(n+1)-4

We multiply parentheses

12n+12-4

We add all the numbers together, and all the variables

12n+8

Back to the equation:

-(12n+8)



We add all the numbers together, and all the variables

15n-(12n+8)+2=0

We get rid of parentheses

15n-12n-8+2=0

We add all the numbers together, and all the variables

3n-6=0

We move all terms containing n to the left, all other terms to the right

3n=6

n=6/3

n=2

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