05(x-6)+2=7(x+2)-12

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Solution for 05(x-6)+2=7(x+2)-12 equation: 



05(x-6)+2=7(x+2)-12

We move all terms to the left:

05(x-6)+2-(7(x+2)-12)=0

We multiply parentheses

5x-(7(x+2)-12)-30+2=0



We calculate terms in parentheses: -(7(x+2)-12), so:

7(x+2)-12

We multiply parentheses

7x+14-12

We add all the numbers together, and all the variables

7x+2

Back to the equation:

-(7x+2)



We add all the numbers together, and all the variables

5x-(7x+2)-28=0

We get rid of parentheses

5x-7x-2-28=0

We add all the numbers together, and all the variables

-2x-30=0

We move all terms containing x to the left, all other terms to the right

-2x=30

x=30/-2

x=-15

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