10-(8+6j)=-9j-2(3j-1)

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Solution for 10-(8+6j)=-9j-2(3j-1) equation: 



10-(8+6j)=-9j-2(3j-1)

We move all terms to the left:

10-(8+6j)-(-9j-2(3j-1))=0

We add all the numbers together, and all the variables

-(6j+8)-(-9j-2(3j-1))+10=0

We get rid of parentheses

-6j-(-9j-2(3j-1))-8+10=0



We calculate terms in parentheses: -(-9j-2(3j-1)), so:

-9j-2(3j-1)

We multiply parentheses

-9j-6j+2

We add all the numbers together, and all the variables

-15j+2

Back to the equation:

-(-15j+2)



We add all the numbers together, and all the variables

-6j-(-15j+2)+2=0

We get rid of parentheses

-6j+15j-2+2=0

We add all the numbers together, and all the variables

9j=0

j=0/9

j=0

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